On this page, you can find the recording of the Exam Training for QM2IB Maths [Quantitative Methods 2 Maths]. Feel free to ask questions in the comment section below, we will answer them 🙂
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The exercise about the determinant(10:20): The tutor explained it step by step except for the 3rd step. How have the numbers in the matrix changed?
found the answer 🙂
What happens in the fourth step? How come 4 disappears and the other numbers change?
Sorry, that question above meant for question 5
Hey, so in order to get to the -5 and 18 you do the “cross-calculation” (-2)*1 -(-5)*4 = 18; 3*1-2*4=-5. Afterwards, -5 is multiplied with -1 and 18 with 1.
3*(-5)-2*(-2) can be left out since it is later multiplied with 0 (first row last column), therefore there is a 0 instead of a 4 in that spot (it is striked out anyways).
I hope this understandable, if you have any doubts just ask again:)
Hi,
Could you please explain why there is a cross-calculation in the 3×3 matrix please (slide 13) ? I thought do a cross-calculation when we have a 2×2 matrix.
Thanks !
Hi Apolline,
We only do it in the 2×2 or what specifically are you referring to? You reduce the large matrix into the smaller ones strategically and keep the cofactors outside to account for the prior steps until you have a 2×2. Let me know whether that makes sense. Best Florian
In the last question, why don’t you multiply the added units by the shadow price? I thought that was how you get the value of change.
We only have to multiply the increase by the shadow price if we want to determine by how much the objective function value changes. However, this questions asks by how much the final value changes. As long as a constraint is binding and the increase or decrease is inside the ranges, the final value of a constraint changes by the same amount of the change in its RHS.
Hi,
On slide 47, I don’t get why the increase of 2.5€ doesn’t impact the final value with an allowable increase of 1 (<2,5€…), but on slide 49, the 30 min increase crosses the 15 min allowable increase so it changes the final value. Does it mean we have to look for the the allowable range (as it is 3 in slide 47, which is bigger than 2.5€) when the price changes; and look for the allowable increase or decrease when minutes or whatever unit other than price changes?
Hi Cyriaque,
it does not change the optimal solution (the final value) as it is inside the range of the allowable increase and decrease. We increase it from 2 Euros to 2.5 Euro, which is an increase of 0.5. Does that make things clearer, otherwise, please let me know!